How can we calculate the radiated power in CST MWS?

dear friends
hi
I embedded an antenna in a lossy medium and I know the S11 and deliver power 1w but i don't know, how should I calculate the radiated power?
the return loss Figure is resonated at 402MHz to -20dB .
Is this solution sorrect?
S11=10log(P(ref)/P(inc)))=>
-20=10log(P(reflected)/1w)=>P(reflected)=0.01w
P(inc)=P(radiated)+P(ref)=>P(radiated)=0.99

but I have a lossy medium in which the antenna is located.that is
P(radiated)=P(pure_radiation)+P(Loss)

I know the SAR value 135(mw/g), but I don't know how should I calculate the P(Loss) and then the pure value of the P(pure_radiation).
so ,what's the solution?

p(accept)=p(incidence)*s21=0.99w
p(pure_radiation)=p(accept)*Q
那有木有Q值?。?br />你知道sar沒什么用吧，天線一定不是全向的吧，就算是，也反映不到該點(diǎn)的輻射能量密度，算不了輻射功率的吧。

sorry i don't understandexactly ,would you please explain more?
if the radiation pattern be something like this
how we can calculate the radiated power?

試著翻譯一下樓主的意思，樓主是說把一個(gè)天線放置在一塊有耗介質(zhì)內(nèi)部，現(xiàn)在想得到天線通過有耗介質(zhì)輻射至自由空間的總功率，是嗎？
如果是實(shí)際測量，樓主要如何得到這個(gè)參數(shù)？
PS：如果可能的話，用自己的機(jī)器敲漢字吧。

I found out how should I calculate the radiated power it is calculated from the radiation efficiency of the antenna
radiation efficiency=P(radiated)/P(delivered)
in which the P(delivered)=1w