關(guān)于安捷倫datasheet中一處輸出阻抗匹配的疑惑～

                    Figure23

這是MGA83563的2.5GHz輸出阻抗匹配的　匹配過程及實現(xiàn)，是datasheet中提供的～但不包括紅色部分，紅色部分是自己畫上去的。原文如下：
　Avago’s Touchstone program was used to interpolate the s-parameter data and calculate a Γml of 0.14 ∠172° for 2.5 GHz.
   This Γml point is plotted on the Smith chart in Figure 23 as
Point C, along with an indication of the area of lower impedance
from this point. (The output impedance is expected to
decrease under large signal conditions.) A two-element matching network consisting of a shunt capacitor and series transmission line is chosen to match the output to 50 ohms.
    Referring to the Smith chart in Figure 23, the initial output match
for Γml was determined to be a 0.4 pF shunt capacitor followed by a 0.32-inch length of 50 Ω microstripline.

首先，把我的疑惑說一下：
ａ，我認(rèn)為Ｂ點(diǎn)應(yīng)該在圖中的Ｂ＇點(diǎn)。（至少匹配時要與r=1圓相交）
ｂ，既然要做并聯(lián)電容匹配，就應(yīng)該做導(dǎo)納變換即Ｃ換到Ｃ＇
ｃ，而且對微帶和容抗的計算結(jié)果也有出入，
其次，如果圖中是按導(dǎo)納圓匹配的，也有問題，既然是將輸出阻抗匹配到傳輸線，確定微帶線長時，怎么逆時針旋轉(zhuǎn)反射系數(shù)到Ｂ點(diǎn)呢？應(yīng)該是順時針轉(zhuǎn)到Ｂ＇的、對應(yīng)的導(dǎo)納點(diǎn)阿。

以上是我對這個數(shù)據(jù)手冊的不解，請網(wǎng)站朋友的幫助。